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How can the square-wave generator of Problem 9.11 be used to make a triangular-wave generator Ans: Cascade the integrator of Fig. 9-6 to the output of the square-wave generator Describe an op amp circuit that will simulate the equation 3v1 2v2 v3 vo . Ans. The summer of Fig. 9-4, with RF =R1 3; RF =R2 2, and RF =R3 1, cascaded into the inverting ampli er of Fig. 9-2, with RF =R1 1 The circuit of Fig. 9-36 (called a gyrator) can be used to simulate an inductor in active RC lter design. Assuming ideal op amps, nd (a) the s-domain input impedance Z s and (b) the value of the inductance that is simulated if C 1 nF, R1 2 k , R2 100 k , and R3 R4 10 k . Ans: a Z s sR1 R2 R3 C=R4 ; b 200 mH asp.net upc-a UPC-A . NET Control - UPC-A barcode generator with free . NET ...
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6 Apr 2005 ... Demonstrates a method to draw UPC-A barcodes using C#. ... NET 2003 - 7.87 Kb. Image 1 for Drawing UPC-A Barcodes with C# ... 37.22 A ladder which is 13 feet long leans against a wall. The bottom of the ladder is sliding away from the base of the wall at the rate of 5 feet per second. How fast is the radian measure of the angle between the ladder and the ground changing at the moment when the bottom of the ladder is 12 feet from the base of the wall CHAP. 9] 2 + Z(s) _ R4 1 C R3 0 3 R1 4 + 5 _ 37.23 The beam from a lighthouse 3 miles from a straight coastline turns at the rate of 5 revolutions per minute. How fast is the point P at which the beam hits the shore moving when that point is 4 miles from the point A on the shore directly opposite the lighthouse (see Fig. 37-9) Fig. 9-36 asp.net upc-a Barcode UPC-A - CodeProject
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The UPC-A Code and the assignment of manufacturer ID numbers is controlled in the ... ASP . NET /Windows Forms/Reporting Services/Compact Framework ... For the double integrator circuit of Problem 9.14, if the output is connected to the input so that vi vo , an oscillator is formed. Show that this claim is so, and that the frequency of oscillation is f 1= RC Hz. [Hint: Replace Vo with Vi in (1) of Problem 9.14 to get an expression of the form Vi f s 0: In the logarithmic ampli er circuit of Fig. 9-7, vo must not exceed approximately 0.6 V, or else iD will not be a good exponential function of vD . Frequently, a second-stage inverting ampli er is added as shown in Fig. 0 9-7, so that vo is conveniently large. If the second-stage gain is selected to be Av RF =R1 1=VT , then 0 its output becomes vo ln vi . In the circuit of Fig. 9-7, vD is exponential for 0 iD 1 mA, 0 vi 10 V, 0 and Io 100 pA. Size R, RF , and R1 so that vo is as given above. Ans: R 10 m ; arbitrarily select R1 1 k , and then RF 38:46 k In the logarithmic ampli er of Fig. 9-24, let vS 5 V; VR 10 V; R1 1 k ; R2 10 k ; R3 1 k ; and R4 50 k . The matched BJTs are operating at 258C, with VT 0:026 V. Find (a) v2 and (b) vo (see Problem 9.17). Ans: a 41:8 mV; b 2:13 V Having at your disposal a logarithmic ampli er and an exponential ampli er, devise a circuit that will produce the quotient of two numbers. (Hint: x=y eln x ln y .) Ans: See Fig. 9-37 Fig. 37-9 C(ln V1 _ ln V2) Fig. 9-37 1 (a) Recall the complicated evaluation 0 x 2 dx = 1 in Problem 30.2. If, instead, we choose the antiderivative x 3 /3 and apply the 3 fundamental theorem, 1 0 The unity follower of Fig. 9-13 is the noninverting ampli er of Fig. 9-3 if R1 ! 1 and R2 ! 0. (a) Find the output impedance Rout of the noninverting ampli er of Fig. 9-3 subject to the approximation ii 0.
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